- Prashant singh: Anubhav correct
- thiru malai: Ai= 252.63
- Jisan Islam: Chandan Singhy you are right.
- collegetv: no, because maybe you applied voltage gain for RL= 1.6K (in the current gain formula) but here we have to apply voltage gain for RL= 5.6K
- Venkatesh Mamidi: Ai=252.68
- Sandeep Patil: 128.56
- saikumar edu: Ai=-128.565
- Saurabh Kumar: Ai=252.68
- Anubhav: you always leave the current gain problem ..atleat do one problem of current gain so dat we may clear more,, btw thanku so much for ur efforts.
- Uday kumar: we can grab good knowledge from ur videos .. why won't u do videos on electrical subjects like machines and power electronics.. pls do some videos on power electronics .. I t will be surely helpful to us
- Nithya G: Ai= i0/ii ;
io = -(V0/Rl)
Using CDR @ input; ii = is(Rs/(Rs+Ri));
Thus I0/ii = -(V0/Vs) ((Rs+Ri)/Ri)
= - Avs* ((Rs+Ri)/Ri);
ANS : 128.52
- Arjun Vishwakarma: yes
- Vikram Singh: 128.57 is this correct ???
- Ayan Ghosh: U r awesome ,,ur speed ,way of speaking,, and knowledge..... But please cover up power electronics -- it will be very useful for us
- Chandan Singh: The answer will be
Ai=Io/Ii=Io/Is=-Avl(Zi/Rl);
=-(-353.76)(4/5.6)
=252.6
is it sir ??
- Ridhika Nondy: Thnx
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Two-Port Systems Approach (Solved Problem) |
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